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0=6x^2-10x-100
We move all terms to the left:
0-(6x^2-10x-100)=0
We add all the numbers together, and all the variables
-(6x^2-10x-100)=0
We get rid of parentheses
-6x^2+10x+100=0
a = -6; b = 10; c = +100;
Δ = b2-4ac
Δ = 102-4·(-6)·100
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-50}{2*-6}=\frac{-60}{-12} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+50}{2*-6}=\frac{40}{-12} =-3+1/3 $
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